Posted February 13, 2011 • #story #sudoku #sumdoku #chess #knighted #encode
In this 5th birthday celebratory puzzle, solve 3 linked puzzles to get the final answer. Start with story logic, use it to move digits into the sudoku, and finish off with the encode puzzle at the end!
The Almost-Perfect Timing badge is available for solving this puzzle! If you have an account here on The Griddle, you can enter the codes to unlock it using info from the puzzle.
David Millar • 02/13/11 6:34 pm
Thanks for the comments Grant. Fixed some of the clarity problems with the story problem. Not sure where to go with making the other puzzles more difficult, but after our chat before I'll consider the changes/adjustments in later puzzles.
Will • 07/20/11 7:16 am
Thanks for the suggestion, mathgrant, but I have yet to figure out what the heck this grid means. I now know what K/D spread means, but not anything else. What are the red and blue numbers? What are the numbers that intersect the names and K/D spreads?
Will • 07/20/11 7:19 am
Nevermind, I read further into your post and figured it out. Thanks!
mathgrant • 02/13/11 1:28 pm
Part 1: You may want to label the +15, +12, and +4 as K/D spreads to aid people who've never played any FPS's nor heard of a "K/D spread", and therefore don't instantly recognize +15, +12, and +4 as such. Granted, it was easy to determine what it was by process of elimination, but still. I might also add a "flag captures as" label spanning the Red numbers and the Blue numbers to make it more clear what they mean, and add a sentence to the introduction: "From the clues below, determine each player's K/D spread and the number of flag caps they got as Red and as Blue."
Part 2: As a curiosity, I decided to see how much of this puzzle could be solved without solving Part 1, and only with the knowledge that the given in row 1, for example, is 3, 2, or 7, and if it's 3, the givens in row 2 and 3 can't be 5 or 2, respectively. It turns out that the puzzle can be narrowed down to three solutions, two of which correspond to the same givens. The correct derived from part 1, though, make the solution unique.
Part 3: I figured out the message easily without the first two parts, but they did confirm the answer.